Biết (4x^2-9)(2^(x-1)-1)=0. Giá trị của x là:

$\displaystyle \begin{array}{{>{\displaystyle}l}} \left( 4x^{2} -9\right) .\left( 2^{x-1} -1\right) =0\\ \Leftrightarrow \left[ \begin{array}{l l} 4x^{2} -9=0 & \\ 2^{x-1} -1=0 & \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l l} 4x^{2} =9 & \\ 2^{x-1} =1 & \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l l} x^{2} =\frac{9}{4} & \\ x-1=0 & \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l l} x=\frac{3}{2} ;\ x=\frac{-3}{2} & \\ x=1 & \end{array} \right. \end{array}$