Câu trong ảnh làm như nào các bạn ơi...

Có:
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
x+\widehat{PMN} +2x=180^{0}\\
\Longrightarrow 3x+90^{0} =180^{0}\\
\Longrightarrow x=30^{0}
\end{array}$
Vì a//b ⟹ $\displaystyle t=\widehat{NMb} =2x=2.30=60^{0}$ (hai góc so le trong)
Xét tam giác PMN, có:
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
3y+t+90^{0} =180^{0}\\
\Longrightarrow 3y+60^{0} +90^{0} =180^{0}\\
\Longrightarrow y=10^{0}
\end{array}$
Có: $\displaystyle 3y+2z=180^{0}$ (kề bù)
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
\Longrightarrow 3.10^{0} +2z=180^{0}\\
\Longrightarrow z=75^{0}
\end{array}$
$\displaystyle \Longrightarrow x+y-z+t=30^{0} +10^{0} -75^{0} +60^{0} =25^{0}$