daovantest

Giải: a) Ta có: $a)\frac{4^2{\mathrm{.4}}^3}{2^{10}}$ = $a)\frac{16}{1024}$ = 16/1024 = 1/64 Vậy a = 1/64. b) Ta có: $b)\frac{2^7{\mathrm{.9}}^3}{6^5{\mathrm{.8}}^2}$ = $b)\frac{128}{65536}$ = 128/65536 = 1/512 Vậy b = 1/512. c) Ta có: $c)\frac{5^4{\mathrm{.20}}^4}{{25}^4{\mathrm{.4}}^5}$ = $c)\frac{625}{2560000}$ = 625/2560000 = 1/4096 Vậy c = 1/4096. d) Ta có: $d)\frac{5^4{\mathrm{.9}}^3}{{15}^2{\mathrm{.27}}^3}$ = $d)\frac{625}{3375}$ = 625/3375 = 5/27 Vậy d = 5/27. e) Ta có: $e)\frac{{81}^{20}{\mathrm{.25}}^{55}}{{125}^{36}{\mathrm{.9}}^{40}}$ = $e)\frac{8120}{5512536940}$ = 81/20 * 55/125 * 36/9 * 1/40 = 3/4 Vậy e = 3/4. f) Ta có: $f)\frac{{27}^2{\mathrm{.25}}^5{\mathrm{.2}}^5}{{6.15}^4\mathrm{.18}}$ = $f)\frac{729}{255256.15418}$ = 729/25 * 5/25 * 6.15/4 * 1/18 = 243/100 Vậy f = 243/100. g) Ta có: $g{)}^{*}\frac{2^{2012}{\mathrm{.3}}^{2013}{\mathrm{.5}}^{2014}}{6^{2012}{\mathrm{.25}}^{1007}}$ = $g{)}^{*}\frac{22012}{3201352014}$ = 2^2012 / (3^2013 * 5^2014) * (6^2012 / 25^1007) = 2^2012 * 6^2012 / (3^2013 * 5^2014 * 25^1007) = (2*6)^2012 / (3^2013 * 5^2014 * 25^1007) = 12^2012 / (3^2013 * 5^2014 * 5^2014) = 12^2012 / (3^2013 * 5^4028) Vậy g = 12^2012 / (3^2013 * 5^4028).