MLEM MLEM🥣 LUYỆN TẬP CHUNG: THỰC HIỆN PHÉP TÍNH,$1)~\frac79+\frac5{12}-\frac34;2)~\frac7{-25}+\frac{-18}{25}+\frac4{23}+\frac57+\frac{19}{23};$ $3)~\frac{-2}{17}+\frac{15}{19}+\frac{-15}{17}+\frac{15}{23}+\frac4{19};$,$4)~\frac{-5}{11}+(\frac{-6}{11}+1);5)~1,4.\frac{15}{49}-(\frac45+\frac23):2\frac15;6)(0,75-\frac14):\frac56;$,$7)~(\frac{-3}4+\frac16):(\frac59-\frac16);8)~(\frac78-\frac34).1\frac13-\frac72:5\frac14;9)(4-\frac5{12}):2+\frac5{24};$,$10)~\frac67+\frac57:5-\frac89;$ $11)~1\frac{13}{15}.0,75-(\frac{11}{20}+25\%):\frac75;12)~\frac{-5}{12}.\frac34+\frac{-7}4.\frac3{12}.13)$,$\frac13.\frac45+\frac13.\frac65-\frac43;14)\frac59.\frac7{13}+\frac59.\frac9{13}-\frac59.\frac3{13};15)(-3,2).\frac{-15}{64}+(0,8-2\frac4{15}):3\frac23$,$16)~0,2.\frac{15}{36}-(\frac25+\frac23):1\frac15;17)~\frac{-3}5.\frac57+\frac3{-5}.\frac37+\frac35.\frac{-6}7;18)~\frac{-4}{19}.\frac37+\frac{-3}7.\frac{15}{19}+\frac57;$,$19)~19\frac58:\frac7{12}-15\frac14:\frac7{12};20)\frac25.\frac13-\frac2{15}:\frac15+\frac35.\frac13;21)~\frac47.\frac7{13}+\frac47.\frac9{13}-\frac47.\frac3{13}$,$22)~\frac{-4}7.\frac29+\frac{-4}7.\frac79+2\frac47;23)~\frac{18}{37}+\frac8{24}+\frac{19}{37}-1\frac{23}{24}+\frac23;$,$24)(\frac25)^2+5\frac12.(4,5-2)+\frac{2^3}{(-4)};25)(-\frac12)^2:\frac14-2(-\frac12)^2;$,$26)~125\%.(\frac{-1}2)^2:(1\frac5{16}-1,5)+2022^0;27)~(-2)^3.\frac{-1}{24}+(\frac43-1\frac56):\frac5{12};$,$28)~1,4.\frac{15}{49}-(\frac45+\frac23):2\frac15;$ $29)~\frac7{19}.\frac8{11}+\frac7{19}.\frac3{11}+\frac{12}{19};$,$30)~\frac47:(\frac25.\frac47);31)~(-3,2).\frac{-15}{64}+(0,8-2\frac4{15}):3\frac23;32)(\frac38+\frac{-3}4+\frac7{12}):\frac56+\frac12;$,$33)~\frac12+\frac34-(\frac34-\frac45);34)~0,25:(10,3-9,8)-\frac34;$,$35)1\frac{13}{15}.0,75-(\frac{11}{20}+25\%):\frac73;36)(\frac23+\frac27-\frac14):(-1-\frac37+\frac3{28});$,$37)~\frac{-3}7.\frac59+\frac49.\frac{-3}7+2\frac37;38/-2,4.\frac5{(-4)^2}+(25\%-2\frac35):3\frac2{15};$,$39/~\frac{-3}7+(\frac{-4}7+1);40/~\frac{-1}2+\frac56+\frac13;41/~\frac{10}{11}+\frac4{11}:4-\frac18;$,$42/~\frac14+\frac34.(-\frac12+\frac23);$ $43/~2,4.\frac5{(-4)^2}+(25\%-2\frac35):3\frac2{15}$

Question

Timi · Accepted Answer

1) $\frac{7}{9} + \frac{5}{12} - \frac{3}{4}$

Quy đồng mẫu số ba phân số:
$\frac{7}{9} = \frac{28}{36}$, $\frac{5}{12} = \frac{15}{36}$, $\frac{3}{4} = \frac{27}{36}$
Thực hiện phép tính:
$\frac{28}{36} + \frac{15}{36} - \frac{27}{36} = \frac{28 + 15 - 27}{36} = \frac{16}{36} = \frac{4}{9}$
2) $\frac{7}{-25} + \frac{-18}{25} + \frac{4}{23} + \frac{5}{7} + \frac{19}{23}$
Quy đồng mẫu số các phân số:
$\frac{7}{-25} = \frac{-7}{25}$, $\frac{-18}{25}$, $\frac{4}{23}$, $\frac{5}{7}$, $\frac{19}{23}$
$\frac{-7}{25} + \frac{-18}{25} + \frac{4}{23} + \frac{5}{7} + \frac{19}{23} = \frac{-25}{25} + \frac{23}{23} + \frac{5}{7} = -1 + 1 + \frac{5}{7} = \frac{5}{7}$
3) $\frac{-2}{17} + \frac{15}{19} + \frac{-15}{17} + \frac{15}{23} + \frac{4}{19}$
$\frac{-2}{17} = \frac{-2}{17}$, $\frac{15}{19} = \frac{15}{19}$, $\frac{-15}{17} = \frac{-15}{17}$, $\frac{15}{23} = \frac{15}{23}$, $\frac{4}{19} = \frac{4}{19}$
$\frac{-2}{17} + \frac{15}{19} + \frac{-15}{17} + \frac{15}{23} + \frac{4}{19} = \frac{-17}{17} + \frac{19}{19} + \frac{15}{23} = -1 + 1 + \frac{15}{23} = \frac{15}{23}$
4) $\frac{-5}{11} + (\frac{-6}{11} + 1)$
$\frac{-5}{11}$, $\frac{-6}{11}$, $1 = \frac{11}{11}$
$\frac{-5}{11} + (\frac{-6}{11} + \frac{11}{11}) = \frac{-5}{11} + \frac{5}{11} = 0$
5) $1,4 \cdot \frac{15}{49} - (\frac{4}{5} + \frac{2}{3}) : 2\frac{1}{5}$
$\frac{4}{5} = \frac{12}{15}$, $\frac{2}{3} = \frac{10}{15}$, $2\frac{1}{5} = \frac{11}{5}$
$1,4 \cdot \frac{15}{49} - (\frac{12}{15} + \frac{10}{15}) : \frac{11}{5} = 1,4 \cdot \frac{15}{49} - \frac{22}{15} : \frac{11}{5} = 1,4 \cdot \frac{15}{49} - \frac{22}{15} \cdot \frac{5}{11} = 1,4 \cdot \frac{15}{49} - \frac{2}{3} = \frac{14}{10} \cdot \frac{15}{49} - \frac{2}{3} = \frac{210}{490} - \frac{2}{3} = \frac{3}{7} - \frac{2}{3} = \frac{9}{21} - \frac{14}{21} = \frac{-5}{21}$
6) $(0,75 - \frac{1}{4}) : \frac{5}{6}$
$0,75 = \frac{3}{4}$, $\frac{1}{4}$
$(\frac{3}{4} - \frac{1}{4}) : \frac{5}{6} = \frac{2}{4} : \frac{5}{6} = \frac{1}{2} \cdot \frac{6}{5} = \frac{6}{10} = \frac{3}{5}$
7) $(\frac{-3}{4} + \frac{1}{6}) : (\frac{5}{9} - \frac{1}{6})$
$\frac{-3}{4} = \frac{-9}{12}$, $\frac{1}{6} = \frac{2}{12}$, $\frac{5}{9} = \frac{10}{18}$, $\frac{1}{6} = \frac{3}{18}$
$(\frac{-9}{12} + \frac{2}{12}) : (\frac{10}{18} - \frac{3}{18}) = \frac{-7}{12} : \frac{7}{18} = \frac{-7}{12} \cdot \frac{18}{7} = \frac{-18}{12} = \frac{-3}{2}$
8) $(\frac{7}{8} - \frac{3}{4}) \cdot 1\frac{1}{3} - \frac{7}{2} : 5\frac{1}{4}$
$\frac{7}{8}$, $\frac{3}{4} = \frac{6}{8}$, $1\frac{1}{3} = \frac{4}{3}$, $\frac{7}{2}$, $5\frac{1}{4} = \frac{21}{4}$
$(\frac{7}{8} - \frac{6}{8}) \cdot \frac{4}{3} - \frac{7}{2} : \frac{21}{4} = \frac{1}{8} \cdot \frac{4}{3} - \frac{7}{2} \cdot \frac{4}{21} = \frac{4}{24} - \frac{28}{42} = \frac{1}{6} - \frac{2}{3} = \frac{1}{6} - \frac{4}{6} = \frac{-3}{6} = \frac{-1}{2}$
9) $(4 - \frac{5}{12}) : 2 + \frac{5}{24}$
$4 = \frac{48}{12}$, $\frac{5}{12}$, $2 = \frac{2}{1}$, $\frac{5}{24}$
$(\frac{48}{12} - \frac{5}{12}) : \frac{2}{1} + \frac{5}{24} = \frac{43}{12} : \frac{2}{1} + \frac{5}{24} = \frac{43}{12} \cdot \frac{1}{2} + \frac{5}{24} = \frac{43}{24} + \frac{5}{24} = \frac{48}{24} = 2$
10) $\frac{6}{7} + \frac{5}{7} : 5 - \frac{8}{9}$
$\frac{6}{7}$, $\frac{5}{7}$, $5 = \frac{5}{1}$, $\frac{8}{9}$
$\frac{6}{7} + \frac{5}{7} \cdot \frac{1}{5} - \frac{8}{9} = \frac{6}{7} + \frac{1}{7} - \frac{8}{9} = \frac{7}{7} - \frac{8}{9} = 1 - \frac{8}{9} = \frac{1}{9}$
11) $1\frac{13}{15} \cdot 0,75 - (\frac{11}{20} + 25\%) : \frac{7}{5}$
$1\frac{13}{15} = \frac{28}{15}$, $0,75 = \frac{3}{4}$, $\frac{11}{20}$, $25\% = \frac{1}{4}$, $\frac{7}{5}$
$\frac{28}{15} \cdot \frac{3}{4} - (\frac{11}{20} + \frac{1}{4}) : \frac{7}{5} = \frac{28}{15} \cdot \frac{3}{4} - (\frac{11}{20} + \frac{5}{20}) : \frac{7}{5} = \frac{28}{15} \cdot \frac{3}{4} - \frac{16}{20} : \frac{7}{5} = \frac{28}{15} \cdot \frac{3}{4} - \frac{4}{5} : \frac{7}{5} = \frac{28}{15} \cdot \frac{3}{4} - \frac{4}{5} \cdot \frac{5}{7} = \frac{28}{15} \cdot \frac{3}{4} - \frac{4}{7} = \frac{21}{15} - \frac{4}{7} = \frac{7}{5} - \frac{4}{7} = \frac{49}{35} - \frac{20}{35} = \frac{29}{35}$
12) $\frac{-5}{12} \cdot \frac{3}{4} + \frac{-7}{4} \cdot \frac{3}{12}$
$\frac{-5}{12}$, $\frac{3}{4}$, $\frac{-7}{4}$, $\frac{3}{12}$
$\frac{-5}{12} \cdot \frac{3}{4} + \frac{-7}{4} \cdot \frac{3}{12} = \frac{-15}{48} + \frac{-21}{48} = \frac{-36}{48} = \frac{-3}{4}$
13) $\frac{1}{3} \cdot \frac{4}{5} + \frac{1}{3} \cdot \frac{6}{5} - \frac{4}{3}$
$\frac{1}{3}$, $\frac{4}{5}$, $\frac{6}{5}$, $\frac{4}{3}$
$\frac{1}{3} \cdot \frac{4}{5} + \frac{1}{3} \cdot \frac{6}{5} - \frac{4}{3} = \frac{4}{15} + \frac{6}{15} - \frac{4}{3} = \frac{10}{15} - \frac{4}{3} = \frac{2}{3} - \frac{4}{3} = \frac{-2}{3}$
14) $\frac{5}{9} \cdot \frac{7}{13} + \frac{5}{9} \cdot \frac{9}{13} - \frac{5}{9} \cdot \frac{3}{13}$
$\frac{5}{9}$, $\frac{7}{13}$, $\frac{9}{13}$, $\frac{3}{13}$
$\frac{5}{9} \cdot \frac{7}{13} + \frac{5}{9} \cdot \frac{9}{13} - \frac{5}{9} \cdot \frac{3}{13} = \frac{35}{117} + \frac{45}{117} - \frac{15}{117} = \frac{65}{117} = \frac{5}{9}$
15) $(-3,2) \cdot \frac{-15}{64} + (0,8 - 2\frac{4}{15}) : 3\frac{2}{3}$
$-3,2 = \frac{-32}{10}$, $\frac{-15}{64}$, $0,8 = \frac{8}{10}$, $2\frac{4}{15} = \frac{34}{15}$, $3\frac{2}{3} = \frac{11}{3}$
$\frac{-32}{10} \cdot \frac{-15}{64} + (\frac{8}{10} - \frac{34}{15}) : \frac{11}{3} = \frac{480}{640} + (\frac{12}{15} - \frac{34}{15}) : \frac{11}{3} = \frac{3}{4} + \frac{-22}{15} : \frac{11}{3} = \frac{3}{4} + \frac{-22}{15} \cdot \frac{3}{11} = \frac{3}{4} + \frac{-2}{5} = \frac{15}{20} + \frac{-8}{20} = \frac{7}{20}$
16) $0,2 \cdot \frac{15}{36} - (\frac{2}{5} + \frac{2}{3}) : 1\frac{1}{5}$
$0,2 = \frac{1}{5}$, $\frac{15}{36}$, $\frac{2}{5}$, $\frac{2}{3}$, $1\frac{1}{5} = \frac{6}{5}$
$\frac{1}{5} \cdot \frac{15}{36} - (\frac{2}{5} + \frac{2}{3}) : \frac{6}{5} = \frac{15}{180} - (\frac{6}{15} + \frac{10}{15}) : \frac{6}{5} = \frac{1}{12} - \frac{16}{15} : \frac{6}{5} = \frac{1}{12} - \frac{16}{15} \cdot \frac{5}{6} = \frac{1}{12} - \frac{80}{90} = \frac{1}{12} - \frac{8}{9} = \frac{3}{36} - \frac{32}{36} = \frac{-29}{36}$
17) $\frac{-3}{5} \cdot \frac{5}{7} + \frac{3}{-5} \cdot \frac{3}{7} + \frac{3}{5} \cdot \frac{-6}{7}$
$\frac{-3}{5}$, $\frac{5}{7}$, $\frac{3}{-5}$, $\frac{3}{7}$, $\frac{3}{5}$, $\frac{-6}{7}$
$\frac{-3}{5} \cdot \frac{5}{7} + \frac{3}{-5} \cdot \frac{3}{7} + \frac{3}{5} \cdot \frac{-6}{7} = \frac{-15}{35} + \frac{-9}{35} + \frac{-18}{35} = \frac{-42}{35} = \frac{-6}{5}$
18) $\frac{-4}{19} \cdot \frac{3}{7} + \frac{-3}{7} \cdot \frac{15}{19} + \frac{5}{7}$
$\frac{-4}{19}$, $\frac{3}{7}$, $\frac{-3}{7}$, $\frac{15}{19}$, $\frac{5}{7}$

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