19/06/2025
19/06/2025
19/06/2025
7.
a)
$\left\lbrack\left(\frac{1}{9}:\frac{8}{27}\right):-\frac{1}{3}\right\rbrack:\frac{81}{128}$
$=\left(\frac{3}{8}:-\frac{1}{3}\right):\frac{81}{128}$
$=-\frac{9}{8}:\frac{81}{128}$
$=-\frac{16}{9}$
b)
$\left(-\frac{7}{15}\right).\frac{5}{8}.\frac{15}{-7}.\left(-32\right)$
$=\left\lbrack\left(-\frac{7}{15}\right).\frac{15}{-7}\right\rbrack.\frac{5}{8}.\left(-32\right)$
$=1.-20$
$=-20$.
8.
a)
$0,5+\frac{1}{3}+0,4+\frac{5}{7}+\frac{1}{6}-\frac{4}{35}$
$=\frac{5}{10}+\frac{1}{3}+\frac{4}{10}+\frac{5}{7}+\frac{1}{6}-\frac{4}{35}$
$=\left(\frac{5}{10}+\frac{4}{10}\right)+\left(\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{5}{7}-\frac{4}{35}\right)$
$=\frac{9}{10}+\frac{1}{2}+\frac{3}{5}$
$=\frac{9+5+6}{10}$
$=2$
b)
$\frac{8}{9}-\frac{1}{72}-\frac{1}{56}-\frac{1}{42}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}$
$=\frac{8}{9}-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)$
$=\frac{8}{9}-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\ldots+\frac{1}{8.9}\right)$
$=\frac{8}{9}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\cdots+\frac{1}{8}-\frac{1}{9}\right)$
$=\frac{8}{9}-\left(1-\frac{1}{9}\right)$
$=\frac{8}{9}-\frac{8}{9}$
$=0$.
9.
a)
$\frac{3}{35}-\left(\frac{3}{5}+x\right)=\frac{2}{7}$
$\frac{3}{35}-\frac{3}{5}-x=\frac{2}{7}$
$-\frac{18}{35}-x=\frac{2}{7}$
$x=-\left(\frac{2}{7}+\frac{18}{35}\right)$
$x=-\frac{4}{5}$
Vậy $x=-\frac{4}{5}$.
b)
$\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0$
$5x-1=0$ hoặc $2x-\frac{1}{3}=0$
$5x=1$ hoặc $2x=\frac{1}{3}$
$x=\frac{1}{5}$ hoặc $x=\frac{1}{6}$
Vậy $x\in\left\lbrace\frac{1}{5};\frac{1}{6}\right\rbrace$.
c)
$\frac{3}{7}+\frac{1}{7}:x=\frac{3}{14}$
$\frac{1}{7}:x=-\frac{3}{14}$
$x=-\frac{3}{14}:\frac{1}{7}$
$x=-\frac{3}{2}$
Vậy $x=-\frac{3}{2}$.
Nếu bạn muốn hỏi bài tập
Các câu hỏi của bạn luôn được giải đáp dưới 10 phút
CÂU HỎI LIÊN QUAN
18/07/2025
18/07/2025
Top thành viên trả lời