tìm x, biết a)x^2-4x+4=0 b)4x^2-8x+4=0 c)(2x-1)^2-25=0 d)(3x-1)^2-16=0 e)(x+1)^2-x(x+5)=16 f)(2x-3)^2-(4x+1)(x+5)=22

a)
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
x^{2} -4x+4=0\\
\Leftrightarrow ( x-2)^{2} =0\\
\Leftrightarrow x-2=0\\
\Leftrightarrow x=0+2\\
\Leftrightarrow x=2\\
\end{array}$
b)
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
x^{2} -8x+4=0\\
\Leftrightarrow x^{2} -2.x.4+16-12=0\\
\Leftrightarrow ( x-4)^{2} =12\\
\Leftrightarrow \left[ \begin{array}{l l}
x-2=\sqrt{12} & \\
x-2=-\sqrt{12} & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
x-2=2\sqrt{3} & \\
x-2=-2\sqrt{3} & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
x=2\sqrt{3} +2 & \\
x=2-2\sqrt{3} & 
\end{array} \right.\\
\end{array}$
c)
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
( 2x-1)^{2} -25=0\\
\Leftrightarrow ( 2x-1)^{2} =25\\
\Leftrightarrow \left[ \begin{array}{l l}
2x-1=5 & \\
2x-1=-5 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
2x=5+1 & \\
2x=-5=1 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
2x=6 & \\
2x=-4 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
x=6:2 & \\
x=-4:2 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
x=3 & \\
x=-2 & 
\end{array} \right.\\
\end{array}$
d)
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
( 3x-1)^{2} -16=0\\
\Leftrightarrow ( 3x-1)^{2} =16\\
\Leftrightarrow \left[ \begin{array}{l l}
3x-1=4 & \\
3x-1=-4 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
3x=4+1 & \\
3x=-4+1 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
3x=5 & \\
3x=-3 & 
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l l}
x=\frac{5}{3} & \\
x=-1 & 
\end{array} \right.\\
\end{array}$