02/11/2023
02/11/2023
02/11/2023
$\displaystyle \begin{array}{{>{\displaystyle}l}}
\mid \frac{3}{4} -\frac{1}{2} x\mid +\frac{1}{3} =\frac{5}{6}\\
\mid \frac{3}{4} -\frac{1}{2} x\mid =\frac{1}{2}
\end{array}$
TH1:$\displaystyle \frac{3}{4} -\frac{1}{2} x >0\Rightarrow x< \frac{3}{2}$
$\displaystyle \begin{array}{{>{\displaystyle}l}}
\Rightarrow \frac{3}{4} -\frac{1}{2} x=\frac{1}{2}\\
\Leftrightarrow \frac{1}{2} x=\frac{1}{4}\\
\Rightarrow x=\frac{1}{2}( TM)
\end{array}$
TH2:$\displaystyle \frac{3}{4} -\frac{1}{2} x< 0\Rightarrow x >\frac{3}{2}$
$\displaystyle \begin{array}{{>{\displaystyle}l}}
\Rightarrow \frac{3}{4} -\frac{1}{2} x=-\frac{1}{2}\\
\Leftrightarrow \frac{1}{2} x=\frac{5}{4}\\
\Rightarrow x=\frac{5}{2}( TM)
\end{array}$
02/11/2023
=> |3/4-1/2 x|=5/6-1/3=1/2
=> 3/4-1/2 x=1/2 hoặc 3/4-1/2 x=-1/2
=> 1/2 x=3/4-1/2 hoặc 1/2 x=3/4+1/2
=> 1/2 x=1/4 hoặc 1/2 x=5/4
=> x=1/2 hoặc x=5/8
02/11/2023
$\text{| }$ $\dfrac{3}{4}$ $\text{–}$ $\dfrac{1}{2}$ $\text{x}$ $\text{| }$ $\text{+}$ $\dfrac{1}{ 3}$ $\text{=}$ $\dfrac{5}{6}$
$\Rightarrow$ $\text{| }$ $\dfrac{3}{4}$ $\text{–}$ $\dfrac{1}{2}$ $\text{x}$ $\text{| }$ $\text{=}$ $\dfrac{5}{6}$ $\text{–}$ $\dfrac{1}{ 3}$
$\Rightarrow$ $\text{| }$ $\dfrac{3}{4}$ $\text{–}$ $\dfrac{1}{2}$ $\text{x}$ $\text{| }$ $\text{=}$ $\dfrac{1}{2}$
Ta có:
TH1: ( $\text{> 0}$ )
$\dfrac{3}{4}$ $\text{–}$ $\dfrac{1}{2}$ $\text{x}$ $\text{=}$ $\dfrac{1}{2}$
$\Rightarrow$ $\dfrac{1}{2}$ $\text{x}$ $\text{=}$ $\dfrac{1}{4}$
$\Rightarrow$ $\text{x = }$ $\dfrac{1}{2}$ $\textit{( TM) }$
TH1: ( $\text{< 0}$ )
$\dfrac{3}{4}$ $\text{–}$ $\dfrac{1}{2}$ $\text{x}$ $\text{=}$ $\text{–}$ $\dfrac{1}{2}$
$\Rightarrow$ $\dfrac{1}{2}$ $\text{x}$ $\text{=}$ $\dfrac{5}{4}$
$\Rightarrow$ $\text{x = }$ $\dfrac{5}{2}$ $\textit{( TM) }$
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