04/02/2024
04/02/2024
Bài 6:
a)
ĐK: $\displaystyle \begin{cases}
x\ \neq \ \pm \ 3 & \\
x\ \neq \ 2 &
\end{cases}$
$\displaystyle \begin{array}{{>{\displaystyle}l}}
P\ =\ \left(\frac{x^{2} \ -\ 3x}{x^{2} \ -\ 9} \ -\ 1\right) \ \ :\ \left(\frac{9\ -\ x^{2}}{x^{2} \ +\ x\ -\ 6} \ -\ \frac{x\ -\ 3}{2\ -\ x} \ -\ \frac{x\ -\ 2}{x\ +\ 3}\right)\\
=\ \left(\frac{x^{2} \ -\ 3x\ -\ \left( x^{2} \ -\ 9\right)}{x^{2} \ -\ 9}\right) \ \ :\ \left(\frac{9\ -\ x^{2}}{( x\ +\ 3)( x\ \ -\ 2)} \ +\ \frac{x\ -\ 3}{x\ -\ 2} \ -\ \frac{x\ -\ 2}{x\ +\ 3}\right)\\
=\ \ \left(\frac{x^{2} \ -\ 3x\ -\ x^{2} \ +\ 9}{x^{2} \ -\ 9}\right) \ \ :\ \left(\frac{9\ -\ x^{2}}{( x\ +\ 3)( x\ \ -\ 2)} \ +\ \frac{( x\ -\ 3)( x\ +\ 3)}{( x\ +\ 3)( x\ \ -\ 2)} \ -\ \frac{( x\ -\ 2)^{2}}{( x\ +\ 3)( x\ \ -\ 2)}\right)\\
=\ \left(\frac{-3x\ +\ 9}{x^{2} \ -\ 9}\right) \ :\ \left(\frac{9\ -\ x^{2} \ +\ ( x\ -\ 3)( x\ +\ 3) \ -\ ( x\ -\ 2)^{2}}{( x\ +\ 3)( x\ \ -\ 2)}\right)\\
=\ \left(\frac{-3( x\ -\ 3)}{( x\ -\ 3)( x\ +\ 3)}\right) \ :\ \left(\frac{9\ -\ x^{2} \ +\ x^{2} \ -\ 9\ -\ ( x\ -\ 2)^{2}}{( x\ +\ 3)( x\ \ -\ 2)}\right)\\
=\ \frac{-3}{x\ +\ 3} \ :\ \frac{-( x\ -\ 2)^{2}}{( x\ +\ 3)( x\ -\ 2)}\\
=\ \frac{-3}{x\ +\ 3} \ :\ \frac{-( x\ -\ 2)}{x\ +\ 3}\\
=\ \frac{-3}{x\ +\ 3} \ .\ \frac{x\ +\ 3}{-( x\ -\ 2)} \ =\ \frac{-3}{-( x\ -\ 2)} \ =\ \frac{3}{x\ -\ 2}
\end{array}$
b)
$\displaystyle \begin{array}{{>{\displaystyle}l}}
x^{3} \ -\ 4x\ =\ 0\\
\Leftrightarrow \ x\left( x^{2} \ -\ 4\right) \ =\ 0\\
\Leftrightarrow \ x( x\ -\ 2)( x\ +\ 2) \ =\ 0\\
\Leftrightarrow \ \left[ \begin{array}{l l}
x\ =\ 0\ ( n)\\
x\ =\ 2\ ( l)\\
x\ =\ -2\ ( n)
\end{array} \right.\\
+) \ x\ =\ 0\ \Longrightarrow \ P\ =\ \frac{3}{0\ -\ 2} \ =\ \frac{-3}{2}\\
+) \ x\ =\ -2\ \Longrightarrow \ P\ =\ \frac{3}{-2\ -2} \ =\ \frac{-3}{4}
\end{array}$
Ko cs đâu
04/02/2024
Natsuki cảm ơn ạ
04/02/2024
a) DK : x khác {3;-3;2}
P=(x^2-3x/x^2-9 - 1) : (9-x^2/x^2+x-6 - x-3/2-x - x-2/x+3)
= [x(x-3)/(x-3)(x+3) -1 ] : [ (3-x)(3+x)/(x+3)(x-2) - x-3/2-x - x-2/x+3]
= (x/x+3 - 1) : (3-x/x-2 + x-3/x-2 - x-2/x+3)
= x-(x+3)/x+3 : (3-x+x-3/x-2 - x-2/x+3)
= -3/x+3 : (- x-2/x+3)
= -3/x+3 . x+3/-(x-2)
= 3/x-2
b) x^2 - 4x = 0 <=> x(x-4)=0
=> x=0 hay x=4 (TMDK)
x=0 => P = 3/0-2 = -3/2
x=4 => P = 3/4-2 = 3/2
Ko cs đâu
04/02/2024
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