Xét tinhs đúng/ sai.Một hộp chứa 30 tấm thẻ đánh số từ 1 đến 30, hai tấm thẻ khác nhau đánh hai số khác nhau. Lấy ngẫu nhiên một tấm thẻ từ hộp khi đó xác suất để lấy được

To solve this problem, we can use the concept of probability. a) The probability of drawing a card divisible by 3 is $$. There are 10 cards (3, 6, 9, ..., 30) divisible by 3 out of a total of 30 cards. Therefore, the probability is $$. b) The probability of drawing a card divisible by 4 is $$. There are 7 cards (4, 8, ..., 28) divisible by 4 out of a total of 30 cards. Therefore, the probability is $$. c) The probability of drawing a card divisible by both 3 and 4 is $$. There is only one card (12) divisible by both 3 and 4 out of a total of 30 cards. Therefore, the probability is $$. d) The probability of drawing a card divisible by either 3 or 4 is the sum of probabilities from parts (a) and (b), minus the probability from part (c). Therefore, it's $$. So the final answers are: - Probability of drawing a card divisible by $$: $$ - Probability of drawing a card divisible by $$: $$ - Probability of drawing a card divisible by both $$ and $$: $$ - Probability of drawing a card divisible either $$ or $$: $$ Therefore, we have reached the final given answer for each part.