bài này nữa mn owiii Hoàn thành sơ đồ chuyển hoá,$(C_6H_{10}O_5)_n\stackrel{ extcircled1} ightarrow C_6H_{12}O_6\stackrel{ extcircled2} ightarrow C_2H_5OH\stackrel{ extcircled3} ightarrow CH_3COOH\stackrel{(*)} ightarrow C_2H_5OH\stackrel{ extcircled3} ightarrow CH_3COOH^{(*)}$,$(C_6H_{10}O_5)_n+nH_2O\stackrel{H^+} ightarrow nC_6H_{12}O_6$,$\begin{array}{llll}(1)&CH_3COOC_2H_5&C_6H_{12}O_6&\stackrel{lên~men} ightarrow&C_2H_5OH+2CO_2\ extcircled{(2)}&C_2H_5ONa~(**)&C_2H_5OH&+O_2~xt,~P&CH.COH\end{array}$,$ extcircled2~C_2H_5ONa~(**)~C_2H_5OH+O_2\stackrel{xt,~t^0,~P} ightarrow CH_3COOH+H_2O$,$CH_3COOH+C_2H_5OH\stackrel{H_2SO} ightleftarrows\stackrel{(H_5)}CH_3COOC_2H_5+H_2O$

Question

bài này nữa mn owiii Hoàn thành sơ đồ chuyển hoá,$(C_6H_{10}O_5)_n\stackrel{	extcircled1}ightarrow C_6H_{12}O_6\stackrel{	extcircled2}ightarrow C_2H_5OH\stackrel{	extcircled3}ightarrow CH_3COOH\stackrel{(*)}ightarrow C_2H_5OH\stackrel{	extcircled3}ightarrow CH_3COOH^{(*)}$,$(C_6H_{10}O_5)_n+nH_2O\stackrel{H^+}ightarrow nC_6H_{12}O_6$,$\begin{array}{llll}(1)&CH_3COOC_2H_5&C_6H_{12}O_6&\stackrel{lên~men}ightarrow&C_2H_5OH+2CO_2\	extcircled{(2)}&C_2H_5ONa~(**)&C_2H_5OH&+O_2~xt,~P&CH.COH\end{array}$,$	extcircled2~C_2H_5ONa~(**)~C_2H_5OH+O_2\stackrel{xt,~t^0,~P}ightarrow CH_3COOH+H_2O$,$CH_3COOH+C_2H_5OH\stackrel{H_2SO}ightleftarrows\stackrel{(H_5)}CH_3COOC_2H_5+H_2O$

Accepted Answer

{"userId":5406318,"userName":"hellopune"}

Các phương trình hóa học trong sơ đồ phản ứng là:

$1. (C_6H_{10}O_5)_n + nH_2O \xrightarrow{H^+} nC_6H_{12}O_6$

$2. C_6H_{12}O_6 \xrightarrow{lên\ men} 2C_2H_5OH + 2CO_2$

$3. C_2H_5OH + O_2 \xrightarrow{xt, t^o, P} CH_3COOH + H_2O$

Phản ứng của $C_2H_5OH$:

$1. C_2H_5OH + CH_3COOH \xrightarrow{H_2SO_4, t^o} CH_3COOC_2H_5 + H_2O$

$2. C_2H_5OH + Na \rightarrow C_2H_5ONa + \frac{1}{2}H_2$

$3. C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$