Giúp mih vs ạ Bài 2: Triển khai các biểu thức sau theo hằng đẳng thức,$x^2+4$ $2)~1-4x^2$ $3)~4x^2-9$,$4)|9-25x^2$ $5)~4x^2-25$ $6)~9x^2-36$,$7)~(3x)^2-y^2$ $8)~x^2-(2y)^2$ $9)~(2x)^2-y^2$,$10)~(3x)^2_2-9y^4$ $11)~16x^2-(y^2)^2$ $12)~x^4-(3y^2)^2$,$13)~(x-1)(x+1)$ $14)~(x-5)(x+5)$ $15)~(x-6)(6+x)$,$16)~(2x+1)(2x-1)$ $17)~(x-2y)(2y+x)$ $18)~(5x-3y)(3y+5x)$,$19)~(\frac1x-5)(\frac1x+5)$ $20)(x-\frac32)(x+\frac32)$ $21)(\frac x3-\frac y4)(\frac x3+\frac y4)$,$22)(\frac xy-\frac23)(\frac xy+N)$ $23)(\frac x2+\frac y3)(\frac y3-\frac x2)$ $24)(2x-\frac23)(\frac23+2x)$,$25)(2x+\frac35)(\frac35-2x)$ $26)~(\frac12x-\frac43)(\frac43+\frac12x)$ $27)~(\frac23x^2-\frac y2)(\frac23x^2+\frac y2)$,$28)~(3x-y^2)(3x+y^2)$ $29)~(x^2-2y)(x^2+2y)$ $30)~(x^2-y^2)(x^2+y^2)$,Bài 3: Rút gon biểu thức sau:

Question

Accepted Answer

Bài 2:
1) $x^2+4$ không thể triển khai theo hằng đẳng thức $(a+b)(a-b)=a^2-b^2$ vì nó không có dạng hiệu hai bình phương.

2) $1-4x^2=(1-2x)(1+2x)$

3) $4x^2-9=(2x-3)(2x+3)$

4) $9-25x^2=(3-5x)(3+5x)$

5) $4x^2-25=(2x-5)(2x+5)$

6) $9x^2-36=(3x-6)(3x+6)$

7) $(3x)^2-y^2=(3x-y)(3x+y)$

8) $x^2-(2y)^2=(x-2y)(x+2y)$

9) $(2x)^2-y^2=(2x-y)(2x+y)$

10) $(3x)^2-9y^4=(3x-3y^2)(3x+3y^2)$

11) $16x^2-(y^2)^2=(4x-y^2)(4x+y^2)$

12) $x^4-(3y^2)^2=(x^2-3y^2)(x^2+3y^2)$

13) $(x-1)(x+1)=x^2-1$

14) $(x-5)(x+5)=x^2-25$

15) $(x-6)(6+x)=x^2-36$

16) $(2x+1)(2x-1)=4x^2-1$

17) $(x-2y)(2y+x)=x^2-4y^2$

18) $(5x-3y)(3y+5x)=25x^2-9y^2$

19) $\left(\frac{1}{x}-5\right)\left(\frac{1}{x}+5\right)=\frac{1}{x^2}-25$

20) $\left(x-\frac{3}{2}\right)\left(x+\frac{3}{2}\right)=x^2-\frac{9}{4}$

21) $\left(\frac{x}{3}-\frac{y}{4}\right)\left(\frac{x}{3}+\frac{y}{4}\right)=\frac{x^2}{9}-\frac{y^2}{16}$

22) $\left(\frac{x}{y}-\frac{2}{3}\right)\left(\frac{x}{y}+\frac{2}{3}\right)=\frac{x^2}{y^2}-\frac{4}{9}$

23) $\left(\frac{x}{2}+\frac{y}{3}\right)\left(\frac{y}{3}-\frac{x}{2}\right)=\frac{y^2}{9}-\frac{x^2}{4}$

24) $\left(2x-\frac{2}{3}\right)\left(\frac{2}{3}+2x\right)=4x^2-\frac{4}{9}$

25) $\left(2x+\frac{3}{5}\right)\left(\frac{3}{5}-2x\right)=\frac{9}{25}-4x^2$

26) $\left(\frac{1}{2}x-\frac{4}{3}\right)\left(\frac{4}{3}+\frac{1}{2}x\right)=\frac{x^2}{4}-\frac{16}{9}$

27) $\left(\frac{2}{3}x^2-\frac{y}{2}\right)\left(\frac{2}{3}x^2+\frac{y}{2}\right)=\frac{4}{9}x^4-\frac{y^2}{4}$

28) $(3x-y^2)(3x+y^2)=9x^2-y^4$

29) $(x^2-2y)(x^2+2y)=x^4-4y^2$

30) $(x^2-y^2)(x^2+y^2)=x^4-y^4$

Bài 3:
Để rút gọn biểu thức, chúng ta cần biết biểu thức cụ thể là gì. Vui lòng cung cấp biểu thức cần rút gọn.