giúp mình với ạ cảm ơn mọi người Tính:

$\displaystyle \begin{array}{{>{\displaystyle}l}} \sqrt{2+\sqrt{3}} .\sqrt{8-4\sqrt{3}}\\ =\sqrt{2+\sqrt{3}} .\sqrt{\left(\sqrt{6} -\sqrt{2}\right)^{2}}\\ =\sqrt{2+\sqrt{3}} .|\sqrt{6} -\sqrt{2} |\\ =\sqrt{2+\sqrt{3}}\left(\sqrt{6} -\sqrt{2}\right)\\ =\sqrt{2} .\sqrt{2+\sqrt{3}} .\left(\sqrt{3} -1\right)\\ =\sqrt{8+4\sqrt{3}} .\left(\sqrt{3} -1\right)\\ =\sqrt{\left(\sqrt{3} +1\right)^{2}} .\left(\sqrt{3} -1\right)\\ =|\sqrt{3} +1|.\left(\sqrt{3} -1\right)\\ =\left(\sqrt{3} +1\right)\left(\sqrt{3} -1\right)\\ =3-1\\ =2 \end{array}$