1 ô tô và 1 xe máy cùng khởi hành từ a để đi đến b với vận tốc của mỗi xe không đổi trên toàn bộ quãng đường do vận tốc ô tô lớn hơn vận tốc xe máy là 15km/h nên ô tô đến b sớm hơn xe máy 40 phút biết...

We can solve this problem using the concept of relative speed. Let's denote the speed of the car as $$ (in km/h) and the speed of the motorbike as $$ (in km/h). Given that the car is 15 km/h faster than the motorbike, we have: $$ We also know that the car arrives 40 minutes (or $$ hours) earlier than the motorbike for a distance of 60 km. Using the formula: $$ we can express the time taken by each vehicle to travel 60 km: For car: $$ For motorbike: $$ Given that the car arrives 40 minutes earlier than the motorbike, we have: $$ Now, we can substitute $$ and $$ with their respective expressions in terms of speeds: $$ Substitute $$ into this equation: $$ To solve for $$, we can cross multiply and simplify to get a quadratic equation in terms of $$. After solving this equation, we will find that $$ and then $$ So, the speed of the car is 26.25 km/h and the speed of the motorbike is 11.25 km/h.