làm giúp mình Bài 1: Tính giá trị của biểu thức sau:,$a)~(\sqrt[3]3+\sqrt[3]2)^3$ $c)~\sqrt[3]{162}.\sqrt[3]{-2}.\sqrt[3]{\frac23}$,$b)~(\sqrt[3]5-\sqrt[3]3).(\sqrt[3]{25}+\sqrt[3]{15}+\sqrt[3]9)$ $d)~\sqrt[3]2:\sqrt[3]{16}-\sqrt[3]{22\frac12}:\sqrt[3]{53\frac13}$,Bà

Question

Accepted Answer

Bài 1:
a) Ta có:
$$
(\sqrt[3]{3} + \sqrt[3]{2})^3 = (\sqrt[3]{3})^3 + 3 \cdot (\sqrt[3]{3})^2 \cdot \sqrt[3]{2} + 3 \cdot \sqrt[3]{3} \cdot (\sqrt[3]{2})^2 + (\sqrt[3]{2})^3 
= 3 + 3 \cdot \sqrt[3]{9} \cdot \sqrt[3]{2} + 3 \cdot \sqrt[3]{3} \cdot \sqrt[3]{4} + 2 
= 3 + 3 \cdot \sqrt[3]{18} + 3 \cdot \sqrt[3]{12} + 2 
= 5 + 3 \cdot \sqrt[3]{18} + 3 \cdot \sqrt[3]{12}
$$

b) Ta có:
$$
(\sqrt[3]{5} - \sqrt[3]{3}) \cdot (\sqrt[3]{25} + \sqrt[3]{15} + \sqrt[3]{9}) = (\sqrt[3]{5})^3 - (\sqrt[3]{3})^3 
= 5 - 3 
= 2
$$

c) Ta có:
$$
\sqrt[3]{162} \cdot \sqrt[3]{-2} \cdot \sqrt[3]{\frac{2}{3}} = \sqrt[3]{162 \cdot (-2) \cdot \frac{2}{3}} 
= \sqrt[3]{-64} 
= -4
$$

d) Ta có:
$$
\sqrt[3]{2} : \sqrt[3]{16} - \sqrt[3]{22 \frac{1}{2}} : \sqrt[3]{53 \frac{1}{3}} = \sqrt[3]{\frac{2}{16}} - \sqrt[3]{\frac{45}{2}} : \sqrt[3]{\frac{160}{3}} 
= \sqrt[3]{\frac{1}{8}} - \sqrt[3]{\frac{45}{2} \cdot \frac{3}{160}} 
= \sqrt[3]{\frac{1}{8}} - \sqrt[3]{\frac{135}{320}} 
= \sqrt[3]{\frac{1}{8}} - \sqrt[3]{\frac{27}{64}} 
= \frac{1}{2} - \frac{3}{4} 
= -\frac{1}{4}
$$

Đáp số:
a) $5 + 3 \cdot \sqrt[3]{18} + 3 \cdot \sqrt[3]{12}$
b) $2$
c) $-4$
d) $-\frac{1}{4}$