mọi người ơi giải ra từng ý 1 giúp mình mới

$\displaystyle  \begin{array}{{>{\displaystyle}l}}
1,a,\ 9^{\frac{2}{5}} .27^{\frac{2}{5}}\\
=\left( 3^{2}\right)^{\frac{2}{5}} .\left( 3^{3}\right)^{\frac{2}{5}}\\
=3^{\frac{4}{5}} .3^{\frac{6}{5}}\\
=3^{\frac{10}{5}}\\
=3^{2}\\
=9
\end{array}$
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
b,\ 144^{\frac{3}{4}} :9^{\frac{3}{4}}\\
=( 144:9)^{\frac{3}{4}}\\
=16^{\frac{3}{4}}\\
=\left( 2^{4}\right)^{\frac{3}{4}}\\
=2^{3}\\
=8
\end{array}$
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
c,\ \left(\frac{1}{16}\right)^{-0,75} +0,25^{-\frac{5}{2}}\\
=2^{( -4) .( -0,75)} +2^{-2.\frac{-5}{2}}\\
=2^{3} +2^{5}\\
=8+32\\
=40
\end{array}$
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
d,\ ( 0,04)^{-1,5} -( 0,125)^{-\frac{2}{3}}\\
=\left(\frac{1}{25}\right)^{-1,5} -\left(\frac{1}{8}\right)^{-\frac{2}{3}}\\
=5^{( -2) .( -1,5)} -2^{-3.\frac{-2}{3}}\\
=5^{3} -2^{2}\\
=125-4\\
=121
\end{array}$
$\displaystyle  \begin{array}{{>{\displaystyle}l}}
2,a,\ \ \ \ a^{\frac{1}{3}} .\sqrt{a} =a^{\frac{1}{3}} .a^{\frac{1}{2}} =a^{\frac{5}{6}}\\
\ \ \ \ b,\ \ b^{\frac{1}{2}} .b^{\frac{1}{3}} .\sqrt[6]{b} =b^{\frac{1}{2}} .b^{\frac{1}{3}} .b^{\frac{1}{6}} =b^{\frac{1}{2} +\frac{1}{3} +\frac{1}{6}} =b^{1} =b\ \\
\ \ \ \ c,\ \ a^{\frac{4}{3}} :\sqrt[3]{a} =a^{\frac{4}{3}} :a^{\frac{1}{3}} =a^{\frac{3}{3}} =a^{1} =a
\end{array}$
   $\displaystyle d,\ \sqrt[3]{b} :b^{\frac{1}{6}} =b^{\frac{1}{3}} :b^{\frac{1}{6}} =b^{\frac{1}{3} -\frac{1}{6}} =b^{\frac{1}{6}}$