Giúp mik với mik cần gấp!!! Bài 2: Thực hiện phép tính.,$a)\sqrt3.\sqrt{12}-\frac{\sqrt{98}}{\sqrt2}+\sqrt[3]{-27}$ $b)3\sqrt{12}-5\sqrt{48}+\sqrt{27}-\sqrt3$ $c)2\sqrt{\frac32}+3\sqrt{\frac23}-\sqrt{24}$ d),$(\sqrt5-\sqrt2)^2+\sqrt{40}$ $e)(\sqrt3+\sqrt2)^2-\sqrt{24}$ $f)\sqrt{5+2\sqrt6}-\sqrt3$,$g)\frac{\sqrt3+1}{\sqrt3-1}-\frac{\sqrt3-1}{\sqrt3+1}$ $h)\frac{5+\sqrt5}{\sqrt5+1}-\frac{5-\sqrt5}{\sqrt5-1}$ $i)\sqrt[3]{(\sqrt2-5)^3}+\sqrt[3]{(\sqrt2+5)^3}$,$k)\sqrt[3]{(\sqrt2+1)(3+2\sqrt2)}$ $1)\sqrt[3]{(4-2\sqrt3)(\sqrt3-1)}$ $m)(\frac12\sqrt[3]9-2\sqrt[3]3+3\sqrt[3]{\frac13}):2\sqrt[3]{\frac13}$,Bài 3: Giải các phương trình sau.

Question

Accepted Answer

Bài 2:
a)
$\displaystyle \begin{array}{{>{\displaystyle}l}}
\sqrt{3} .\sqrt{12} -\frac{\sqrt{98}}{\sqrt{2}} +\sqrt[3]{-27}\
=\sqrt{3.12} +\sqrt{\frac{98}{2}} +( -3)\
=\sqrt{36} +\sqrt{49} +( -3)\
=6+7+( -3)\
=-4
\end{array}$
b) $\displaystyle 3\sqrt{12} -5\sqrt{48} +\sqrt{27} -\sqrt{3} =6\sqrt{3} -20\sqrt{3} +3\sqrt{3} -\sqrt{3} =-12\sqrt{3}$
c) $\displaystyle 2\sqrt{\frac{3}{2}} +3\sqrt{\frac{2}{3}} -\sqrt{24} =\frac{2\sqrt{3}}{\sqrt{2}} +\frac{3\sqrt{2}}{\sqrt{3}} -2\sqrt{6} =\sqrt{6} +\sqrt{6} -2\sqrt{6} =0$
d) $\displaystyle \left(\sqrt{5} -\sqrt{2} ight)^{2} +\sqrt{40} =5-2\sqrt{10} +2+2\sqrt{10} =7$
e) $\displaystyle \left(\sqrt{3} +\sqrt{2} ight)^{2} -\sqrt{24} =3+2\sqrt{6} +2-2\sqrt{6} =5$

f) $\displaystyle \sqrt{5+2\sqrt{6}} -\sqrt{3} =\ \sqrt{\left(\sqrt{2} +\sqrt{3} ight)^{2}} -\sqrt{3} =\sqrt{2} +\sqrt{3} -\sqrt{3} =\sqrt{2}$
g)
$\displaystyle \begin{array}{{>{\displaystyle}l}}
\frac{\sqrt{3} +1}{\sqrt{3} -1} -\frac{\sqrt{3} -1}{\sqrt{3} +1}\
=\frac{\left(\sqrt{3} +1 ight)\left(\sqrt{3} +1 ight) -\left(\sqrt{3} -1 ight)\left(\sqrt{3} -1 ight)}{\left(\sqrt{3} +1 ight)\left(\sqrt{3} -1 ight)}\
=\frac{3+1+2\sqrt{3} -\left( 3-2\sqrt{3} +1 ight)}{3-1}\
=\frac{4\sqrt{3}}{2} =2\sqrt{3}
\end{array}$

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